换元积分法这题怎么做
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换元积分法这题怎么做
换元积分法这题怎么做
换元积分法这题怎么做
原式=∫2arctan√x/(1+x)*dx/(2√x)
=∫2arctan√x/[1+(√x)²]d√x
=∫2arctan√xdarctan√x
=(arctan√x)²+C
换元积分法这题怎么做
换元积分法这题怎么做
换元积分法这题怎么做
原式=∫2arctan√x/(1+x)*dx/(2√x)
=∫2arctan√x/[1+(√x)²]d√x
=∫2arctan√xdarctan√x
=(arctan√x)²+C