sin4π/3cos5π/6tan(－4π/3)怎么做,求详细过程sin4π/3乘以cos5π/6乘以tan(－4π/3)=？

sin4π/3cos5π/6tan(－4π/3)怎么做,求详细过程sin4π/3乘以cos5π/6乘以tan(－4π/3)=？
sin4π/3cos5π/6tan(－4π/3)怎么做,求详细过程
sin4π/3乘以cos5π/6乘以tan(－4π/3)=？

sin4π/3cos5π/6tan(－4π/3)怎么做,求详细过程sin4π/3乘以cos5π/6乘以tan(－4π/3)=？
sin cos的周期为2π tan周期为π
sin4π=sin(4π-4π)=sin0=0
3cos5π=3cos(5π-4π)=3cosπ=3*(-1)=-3
6tan(－4π/3)=6tan(－4π/3+π)=6tan(-π/3)=-6tan(π/3)=-6√3

sin(4π/3)*cos(5π/6)*tan(-4π/3)
=-sin(π/3)*(-cos(π/6))*tan(-π/3)
=(√3/2)*(√3/2)*(-√3)
=-3√3/4