集合A={(x,y)|2x+y-2=0},B={(x,y)|(2x+y-3)(x+ay-1)=0},若A包含于B,则a=

集合A={(x,y)|2x+y-2=0},B={(x,y)|(2x+y-3)(x+ay-1)=0},若A包含于B,则a=
集合A={(x,y)|2x+y-2=0},B={(x,y)|(2x+y-3)(x+ay-1)=0},若A包含于B,则a=

集合A={(x,y)|2x+y-2=0},B={(x,y)|(2x+y-3)(x+ay-1)=0},若A包含于B,则a=
A是B的子集
2x+y-2=0
所以2x+y-3不等于0
x+ay-1=0
两边乘以2
2x+2ay-2=0
所以2a=1
a=1/2