如图所示,在△ABC中.如图所示,在△ABC中,AB＝AC,在AB边上取点D,在AC的延长线上取点E,使得BD＝CE,连接DE交BC于点G,求证：DG＝GE

如图所示,在△ABC中.如图所示,在△ABC中,AB＝AC,在AB边上取点D,在AC的延长线上取点E,使得BD＝CE,连接DE交BC于点G,求证：DG＝GE
如图所示,在△ABC中.
如图所示,在△ABC中,AB＝AC,在AB边上取点D,在AC的延长线上取点E,使得BD＝CE,连接DE交BC于点G,求证：DG＝GE

如图所示,在△ABC中.如图所示,在△ABC中,AB＝AC,在AB边上取点D,在AC的延长线上取点E,使得BD＝CE,连接DE交BC于点G,求证：DG＝GE
因为AB=AC,所以△ABC是等腰三角形
所以∠B=∠C,
又因为∠DGB=∠CGE,DB=CE
所以△DBG≌△CEG,
所以DG=GE