x+y=4,y+z=3,x+z=-1

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x+y=4,y+z=3,x+z=-1

x+y=4,y+z=3,x+z=-1
x+y=4,y+z=3,x+z=-1

x+y=4,y+z=3,x+z=-1
x+y=4,
y+z=3
,x+z=-1
由第一个方程得x=4-y带入第三个方程得 4-y+z=-1 即为-y+z=-5
再由第二个方程得y=3-z 带入 -y+z=-5 得-3+z+z=-5 得z=-1
把z=-1带入y=3-z=4 把y=4带入x=4-y=0

三式相加得x+y+z=3再减去1式2式3式分别得出z=-1x=0,y=4

x=0,y=4,z=-1

三式相加可得2(x+y+z)=6
于是x+y+z=3
用它分别与三个式子相减得：
z=-1,x=0,y=4

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