(1)解方程:x/(x-2)=2+2/(x-2) (2)已知:(x+3)/(x-2)平方=A/(x-2)+B/(x-2)平方

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/03 03:47:10
(1)解方程:x/(x-2)=2+2/(x-2) (2)已知:(x+3)/(x-2)平方=A/(x-2)+B/(x-2)平方

(1)解方程:x/(x-2)=2+2/(x-2) (2)已知:(x+3)/(x-2)平方=A/(x-2)+B/(x-2)平方
(1)解方程:x/(x-2)=2+2/(x-2) (2)已知:(x+3)/(x-2)平方=A/(x-2)+B/(x-2)平方

(1)解方程:x/(x-2)=2+2/(x-2) (2)已知:(x+3)/(x-2)平方=A/(x-2)+B/(x-2)平方
(1)x/(x-2)=2+2/(x-2)
方程两边同时乘以x-2,得
x=2(x-2)+2
解得x=2
检验:将x=2代入原方程,分母x-2=0,分式无意义,所以x=2是增根.
所以原方程无解.
(2)(x+3)/(x-2)平方=A/(x-2)+B/(x-2)平方
方程两边同时乘以(x-2)²,得
x+3=A(x-2)+B
则x+3=Ax+B-2A
所以A=1,B-2A=3,解得B=5
所以A=1,B=5

(1)x/(x-2)=2+2/(x-2)移项得:
(x-2)/(x-2)=2
即:1=2
无解
(2)(x+3)/(x-2)平方=(x-2+5)/(x-2)^2
=(x-2)/(x-2)^2+5/(x-2)^2
=1/(x-2)+5/(x-2)^2=A/(x-2)+B/(x-2)平方
对应系数:A=1,B=5

x/(x-2)=2+2/(x-2)
x=2(x-2) +2
x=2x-4 +2
x=2x-2
2x-x=2
x=2
经检验x=2是增根,所以方程无解
(x+3)/(x-2)^2=A/(x-2)+B/(x-2)^2
(x+3)=A(x-2)+B
x+3=Ax-2A+B
x+3=Ax-2A+B
A=1,-2A+B=3
-2+B=3
B=5