用复变函数证明arctan (1/2) + arctan (1/3) =π/4
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用复变函数证明arctan (1/2) + arctan (1/3) =π/4
用复变函数证明arctan (1/2) + arctan (1/3) =π/4
用复变函数证明arctan (1/2) + arctan (1/3) =π/4
(-1/x 2;) = 1/(1 x 2;) - 1/(1 x 2;) =0 就是说f(x)=c是一个常数 令x=1有,f(1)=arctan1 arctan1 =π/4 π/4 =π
用复变函数证明arctan (1/2) + arctan (1/3) =π/4
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