As shown below,AB is vertical to BC,AD=EC=4cm,DB=BE=6cm.So what is the area of the shaded part inpicture?

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As shown below,AB is vertical to BC,AD=EC=4cm,DB=BE=6cm.So what is the area of the shaded part inpicture?

As shown below,AB is vertical to BC,AD=EC=4cm,DB=BE=6cm.So what is the area of the shaded part inpicture?
As shown below,AB is vertical to BC,AD=EC=4cm,DB=BE=6cm.So what is the area of the shaded part in
picture?

As shown below,AB is vertical to BC,AD=EC=4cm,DB=BE=6cm.So what is the area of the shaded part inpicture?
连接AC,设ADCE交点为O (以下省略三角形号)
Sabc=Sadc+Sabe-Sado
即 :1/2 * 10 * 10 = 1/2*4*10 + 1/2*6*10 - Sado
Sado=10
因 :Sado= 1/2*4*10 - Saoc
Sceo=1/2*4*10 - Saoc
所以 Sceo = Sado =10
shaded part:Sceo + Sado =10 +10= 20cm平方

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