已知x-y=9,xy=5.求(x+y)(x+y)的值?
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已知x-y=9,xy=5.求(x+y)(x+y)的值?
已知x-y=9,xy=5.求(x+y)(x+y)的值?
已知x-y=9,xy=5.求(x+y)(x+y)的值?
x-y=9
(x-y)²=9²
x²-2xy+y²=81
x²+y²=81+2xy=91
所以(x+y)²
=x²+y²+2xy
=91+10
=101
(x+y)(x+y)=(x-y)^2+4xy=9*9+4*5=101
x-y=9
(x-y)²=9²
x²-2xy+y²=81
x²+y²=81+2xy=91
所以(x+y)²
=x²+y²+2xy
=91+10
=101
(x+y)^2=(x-y)^2+4xy=81+20=101
(x+y)(x+y)
=(x+y)²
=(x-y)²+4xy
=81+20
=101
(x+y)(x+y)
=(x+y)²
=x²+2xy+y²
=x²-2xy+y²+4xy
=(x-y)²+4xy
已知x-y=9,xy=5
所以上式=9²+4*5
=81+20
=101
x-y=9 方程两边平方推出 x∧2+y∧2=81+2xy=91 所以 (x+y)(x+y)=x∧2+y∧2+2xy=91+10=101
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