z=sin(sqrt(x^2+y^2))/sqrt(x^2+y^2),-8≤x,y≤8； 用matlaB怎么编程!

z=sin(sqrt(x^2+y^2))/sqrt(x^2+y^2),-8≤x,y≤8； 用matlaB怎么编程! MATLAB z=100000*sin(y*pi/180)/(17*sqrt(3+sin(2*x*pi/180)));是不是缺几个点 求方程Sqrt(x+y)(z+1)+ Sqrt(y+z)(x+2)+ Sqrt(z+x)(y+3)=2/3(x+y+z)的正实数解Sqrt是开根号 matlab程序如下,不知道哪里出错了,说矩阵维数不符合x=1:10;z=asin(sin(x)./1.736);y=cos(30.4+pi./180.*z)./sqrt(1-1.736.^2*sin(30.4+pi./180.*z).^2)*cos(pi./180.*x)./sqrt(1-1./1.736.^2*sin(pi./180.*x).^2);plot(x,y);提示错误是内矩 matlab 三维绘图问题用mesh绘制二元函数z=sin(sqrt(x.^2+y.^2))/sqrt(x.^2+y.^2) 在(-8,8)上的三维网面图 MATLAB中出现Too many output arguments在M-File中输入x=-3*pi:3*pi;y=x;[X,Y]=meshgrid(x,y);R=sqrt(x.^2+y.^2)+eps;Z=sin(R)./R;[dzdx,dzdy]=gradient(Z);dzdr=sqrt(dzdx.^2+dzdy.^2);surf(X,Y,Z,abs(dzdr))corlormap(spring)alphamap('rampup')corlorbar保 z=sqrt(a^2-x^2-y^2)的质心坐标求 z=sqrt(a^2-x^2-y^2)的质心坐标 关于 MATLAB 绘三维图的问题%xyz有以下关系：syms x y z ；a=6;S=a+x;B=sqrt(a^2+x^2+2*a*x*cos(y));H=B/S;c=atan(x*sin(y)/(a+x*cos(y)));z=H*(1-a)*sin(c)/sqrt(S^2+B^2)/(1+sqrt(1-H^2));% 然后我想绘出关于xyz的三维图：x=0:0.1:1;y=- matlab中Warning:Matrix is singular to working precision.是什么错误,应该怎么解决,最好具体点>> x=-8:0.01:8;>> y=-8:0.01:8;>> [X,Y]=meshgrid(x,y);>> Z=(sin(sqrt(X.^2+Y.^2)))/sqrt(X.^2+Y.^2);surf(X,Y,Z)Warning:Matrix is singular to worki mathematica8.0中如何求带根号的函数最小值,函数为z=10 Sqrt[(x - 1)^2 + (y - 5)^2] + 16 Sqrt[(x - 3)^2 + (y - 4)^2] + 6 Sqrt[(x - 5)^2 + (y - 3)^2] + 11 Sqrt[(x - 4)^2 + (y - 2)^2] + 7 Sqrt[(x - 2)^2 + (y - 1)^2] + 4 Sqrt[(x - 2)^2 + y^2 matlab 代码运行错误x=0:0.1:pi;y=1:0.1:5;[X,Y]=meshgrid(x,y);z=(pi/3)+asin(sin(X)*sqrt(Y.^2-sin(X).^2)-cos(X)*sin(pi/3))-Y;mesh(X,Y,Z) matlab 已知x,y两组数据,求对应的z=f(x,y)>> x=-8:0.5:8;>> y=-8:0.5:8;>> z=sin(sqrt(x^2+y^2))/sqrt(x^2+y^2)Error using ==> mpowerInputs must be a scalar and a square matrix.求问哪儿错了 MATLAB Index exceeds matrix dimensions问题for i=1:90;lac=lab*cos(th1)+sqrt(lbc^2-(lab*sin(th1))^2);l3=sqrt((l1-lac)^2+(l2)^2);x=(l1-lac)/l2;y=(l3^2+led^2-lcd^2)/(2*l3*led);z=l1-lab*cos(th1)-sqrt(lbc^2-(lab*sin(th1)^2));a=sqrt(z^2-l2^2);z1=lab*sin(t C语言,输入三组成三角形#include main(){int x,y,z,l;int s=sqrt(10);scanf(x=%d y=%d z=%d,&x,&y,&z);while((x+y)>z&&(x+z)>y&&(y+z)>x){if ((x+y)>z&&(x+z)>y&&(y+z)>x){printf(x=%d y=%d z=%d,x,y,z);l=x+y+z;printf(L=%d,l);s=sqrt((l/2)*(l/2-x)*( 求z=sqrt(a^2-x^2-y^2)的质心坐标 cosh(z)=sqrt（x^2+y^2）图像用maple如何显示 MATLAB曲面绘制绘制曲面z=sqrt(4-x^2-y^2) 求高手解答用Matlab 如何在matlab编程求这个方程组的解啊?已知a,b,c方程组72.8*(1+cos(a)）=2*(SQRT(x*21.8)+SQRT(25.5*y)+SQRT(25.5*z))50.8*(1+cos(b))=2*SQRT(x*50.8)48*(1+cos(c))=2*(SQRT(x*29)+SQRT(47*y)+SQRT(1.92*z))求x,y,z假设