化简 :sin(a+b)cos(r-b)-cos(b+a)sin(b-r) sin(a-b)sin(b-r)-cos(a-b)cos(r-b)sin(a+b)cos(r-b)-cos(b+a)sin(b-r) 和 sin(a-b)sin(b-r)-cos(a-b)cos(r-b)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 14:47:57
化简 :sin(a+b)cos(r-b)-cos(b+a)sin(b-r) sin(a-b)sin(b-r)-cos(a-b)cos(r-b)sin(a+b)cos(r-b)-cos(b+a)sin(b-r) 和 sin(a-b)sin(b-r)-cos(a-b)cos(r-b)

化简 :sin(a+b)cos(r-b)-cos(b+a)sin(b-r) sin(a-b)sin(b-r)-cos(a-b)cos(r-b)sin(a+b)cos(r-b)-cos(b+a)sin(b-r) 和 sin(a-b)sin(b-r)-cos(a-b)cos(r-b)
化简 :sin(a+b)cos(r-b)-cos(b+a)sin(b-r) sin(a-b)sin(b-r)-cos(a-b)cos(r-b)
sin(a+b)cos(r-b)-cos(b+a)sin(b-r) 和 sin(a-b)sin(b-r)-cos(a-b)cos(r-b)

化简 :sin(a+b)cos(r-b)-cos(b+a)sin(b-r) sin(a-b)sin(b-r)-cos(a-b)cos(r-b)sin(a+b)cos(r-b)-cos(b+a)sin(b-r) 和 sin(a-b)sin(b-r)-cos(a-b)cos(r-b)
第一个:=sin(a+b)cos(-(b-r))-cos(b+a)sin(b-r)
=sin(a+r)
第二个:=-cos(a+r)

0.0

sin(a+b)cos(r-b)+cos(b+a)sin(r-b)=sin(a+b+r-b)=sin(a+r)

利用两角和与差的正弦余弦公式易得:
sin(a+b)cos(-(b-r))-cos(b+a)sin(b-r) =sin(a+r)
sin(a-b)sin(b-r)-cos(a-b)cos(r-b)=-cos(a+r)