用因式分解法解高次方程,(1)x^3+2x^2-3=0 (2)x^3-x-6=0用因式分解法解高次方程,(1)x^3+2x^2-3=0(2)x^3-x-6=0

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 08:36:56
用因式分解法解高次方程,(1)x^3+2x^2-3=0 (2)x^3-x-6=0用因式分解法解高次方程,(1)x^3+2x^2-3=0(2)x^3-x-6=0

用因式分解法解高次方程,(1)x^3+2x^2-3=0 (2)x^3-x-6=0用因式分解法解高次方程,(1)x^3+2x^2-3=0(2)x^3-x-6=0
用因式分解法解高次方程,(1)x^3+2x^2-3=0 (2)x^3-x-6=0
用因式分解法解高次方程,
(1)x^3+2x^2-3=0
(2)x^3-x-6=0

用因式分解法解高次方程,(1)x^3+2x^2-3=0 (2)x^3-x-6=0用因式分解法解高次方程,(1)x^3+2x^2-3=0(2)x^3-x-6=0
(1)x^3+2x^2-3=(x³-1)+2x²-2=(x-1)(x²+x+1)+2(x-1)(x+1)
=(x-1)(x²+3x+3)=0 x²+3x+3=0中 判别式△=9-12

(1)对原式分解得x^2(x-1)+3(x-1)(x+1)
=(x-1)(x^2+3x+3